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| re:updatableViews | 29 Sep 2006 23:04 GMT | 7 |
Dear fellow programmers, The problem with an in memory database which you want in case of 2 tier applications is that you dont know where to start inserting or deleting records in the actual (server) database. Thats why you might
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| cyclical redundancy checksum algorithm(s)? | 28 Sep 2006 18:33 GMT | 5 |
I just finished reading one of Ralph Kimball's books. In it he mentions something called a cyclical redundancy checksum (crc) function. A crc function is a hash function that generates a checksum. I am wondering a few things. A crc function would be extremely useful
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| BCNF: superkey or candidate key ? | 28 Sep 2006 13:19 GMT | 21 |
C.J. Date in a recent text defines BCNF in terms of superkey. ... every nontrivial FD A -> B satisfied by R, A is a superkey for R. Previously he (and others) defined it where A had to be a candidate key (which is irreducible).
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| B+ tree - help | 27 Sep 2006 13:07 GMT | 4 |
Ok, I am looking at this question about b+ trees and I just don't get it. Here is the question: A given B+-tree is stored on a disk with blocks containing 512 bytes each. The indexed key, data pointer and pointer to a sub-tree occupy 8
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| Using the same FK in a table more then once | 23 Sep 2006 16:21 GMT | 1 |
I've got a table [User] with which is related to [Character] by 2 relationships. Now, Access seems to be complaining about this and is displaying the table twice with different aliases in the Relationship view..
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| 3 value logic. Why is SQL so special? | 22 Sep 2006 17:40 GMT | 121 |
I know that visual basic, lisp, python, c , c++ , perl, all have 2 value logic. What makes SQL so special that it needs 3vl when all these langauges make do with 2vl?
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| Extending binary NOR | 22 Sep 2006 16:51 GMT | 2 |
This is an offshoot of the discussion of Idempotence and "Replication Sensitivity". I prefer to start a new discussion, because the thread drift is too great. Extending the concept of binary NOR so that is can operate on a column of
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| Managing Hierarchical Data - The Nested Set Model - insert node | 21 Sep 2006 20:26 GMT | 1 |
Sorry for my bad english. I want to add a child(Tom) to Chuck but not on the left of DONNA but on the right of FRED. Can You help me ?
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| Columns without names | 21 Sep 2006 15:30 GMT | 43 |
Faced with a data collection something like: Tom is aged 20, Dick is aged 30 and Harry is aged 40 I find it apt to view a relation predicate for them as: "There is a people_relationship where name is X and age is Y"
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| Nested structures | 21 Sep 2006 14:23 GMT | 12 |
Some, but not all, of you will find this new IDC paper entitled "Because Not All Data is Flat: IBM's U2 Extended Relational DBMSs" to be of interest. Other than the fact that the term "flat" is used, which I know can be
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| Idempotence and Projection | 20 Sep 2006 15:13 GMT | 5 |
If f(x) = SELECT * FROM x GROUP BY * then I would expect f(x) = x provided that x is a relational table. In other words, I expect that projecting a relation into (or it it onto?) its own space is an idempotent operation.
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| Who first (publicly) asserted 3NF is "good enough"? | 19 Sep 2006 16:39 GMT | 14 |
It has always seemed to me that nothing looks more obviously and intuitively wrong than a table that is in third normal form (3NF) but not also 4NF. Furthermore I rarely see violations of 4NF "in the wild" in databases intended to support core business transaction processing (as ...
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| Ternary Relationship cardinality | 19 Sep 2006 13:00 GMT | 10 |
I am working on an assignment which has 2 ternary relationship. I'm can't figure out their cardinality. Maybe I am going through one of those mental blocks... Can someone give me some cardinality examples for N-ary relationships?
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| Real world issue: How to "split" queries in presence of record replication and replication sensitive aggregate functions ? | 19 Sep 2006 09:37 GMT | 57 |
I 'd like to repropose my original problem which got lost among vain fights and pollution. I am infact trying to write as an exercise a "reporting" program. Or
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| Multiple keys and transition constraints | 19 Sep 2006 08:51 GMT | 14 |
Given a relation schema R {A, B, C}, where A and B are each candidate keys. If the current extension is r {{A:1, B:9, C:3} {A:2, B:8, C:4}}
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